Here ,
$L1$=$\left \{ P^{x}Q^{y}| x>0,y>0\right \}$
So, $L1$ =$\left\{PQ, P^2Q,PQ^2,P^2Q^2,......\right\}$
Simply it's any number of $P$ followed by any number of $Q$ and smallest string possible is $PQ$ . The end of every string should be $ 'Q'$ .
$L2$=$\left \{ P^{x}Q^{y}P^z| x>0,y\geq 0,z>0\right \}$
So, $L2$=$\left \{ PP,PQP,PPQQP,PPQQP,......\right \}$
Here smallest possible string is $PP$.Here every string end with P.
So if we make the intersection of $L1\cap L2=\left \{ \right \}$.
As L1 end with $Q$ and L2 end with $P$. So Intersection would be empty set.
So it is regular, CSL and CFL all the above.