Answer is Option C
The equation of line, from coordinates $(1,2)$ to $(3,0)$, where $|x-1|=(x-1)$
$(y-2)=\dfrac{(0-2)}{(3-1)}(x-1)$
$y=2-(x-1)$
$y=2-|x-1|$
The equation of line, from coordinates $(-3,-2)$ to $(1,2)$, where $|x-1|=-(x-1)$
$(y-(-2)) =\dfrac{(2-(-2))}{(1-(-3))}(x-(-3))$
$y=x+1$
$y=2-(-(x-1))$
$y=2-|x-1|$
Note :Equation of line when two coordinates $(x_2,y_2)$ and $(x_1,y_1)$ are given is $(y-y_1)=\dfrac{(y_2-y_1)}{(x_2-x_1)}(x-x_1)$