0 0 votes Given the tight asymptotic bound for the recurrence equation : T(n) = 2T($\frac{n }4{}$) + 1 O(√ n) Ω(√ n) θ(√ n) O(n^2) Using master’s theorem, the result comes to be θ(√ n). Thus option A,B,C are definitely correct. According to the solutions option D is incorrect. I don’t get it why. Can’t we write (√ n) = O(n^2) ? Or is it because we are asked for the tightest asymptotic bound? Please do let know! Algorithms multiple-selects + – Aryanzzzz 1.1k views answer comment Share Follow Print See all 8 Comments 8 8 Comments reply Show 5 previous comments Kabir5454 commented Jan 14, 2023 reply Follow flag It will be correct if “tight” keyword will not be there ? 0 0 replyShare ankitgupta.1729 commented Jan 14, 2023 reply Follow flag haan bhai... 1 1 replyShare Aryanzzzz commented Jan 16, 2023 reply Follow flag yes, i got it now. Thanks a lot! 1 1 replyShare Please log in or register to add a comment.