1 votes 1 votes What is the earliest stage compiler error for the following C code snippet: int x = @33; Lexical Error Syntax Error Semantic Error None Compiler Design compiler-design lexical-analysis error-detection + – Souvik33 asked Jan 12, 2023 Souvik33 592 views answer comment Share Follow See 1 comment See all 1 1 comment reply Shubhodeep commented Jan 12, 2023 reply Follow Share The lexical analyser will catch this error as we know in any valid assignment numbers must belong to (0-9), @ is an illegal character Read more from here : https://www.geeksforgeeks.org/lexical-error/ 1 votes 1 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes Answer: Option A) Lexical Error The compiler will show a lexical error because of the "@" symbol in $@33$. It is not a valid character for variable assignment in the C programming language. An identifier can only have alphanumeric characters (a-z , A-Z , 0-9) (i.e. letters and digits) and underscore $(\_)$ symbol. Abhrajyoti00 answered Jan 12, 2023 • selected Jan 12, 2023 by Souvik33 Abhrajyoti00 comment Share Follow See all 3 Comments See all 3 3 Comments reply Souvik33 commented Jan 12, 2023 reply Follow Share Thanks,Just to comfirm "int a = Y34_" lexical won't catch this right? 2 votes 2 votes Abhrajyoti00 commented Jan 12, 2023 reply Follow Share @Souvik33 Yes, it will not generate lexical error because the variable name "Y34_" is a valid token. It will be raised as a semantic error 1 votes 1 votes Souvik33 commented Jan 13, 2023 reply Follow Share Thanks @Abhrajyoti00 1 votes 1 votes Please log in or register to add a comment.
1 votes 1 votes The earliest stage compiler error for the given C code snippet is a lexical error. This is because @ is not a valid token in the C language, so the compiler would detect it as a lexical error at the very beginning of the compilation process. Johnny1001 answered Jan 15, 2023 Johnny1001 comment Share Follow See all 0 reply Please log in or register to add a comment.