IITM2012

Question

What will be printed by following statement : printf(“%d”,scanf(“%d”,&n));

Answer 1

Scanf returns the no of inputs scanned successfully (if format string does not match scan can fail) and printf returns no of characters printed on the screen , so here 1 is returned by scanf (provided we enter a valid integer) and hence 1 is printed on the screen

Answer 2

scanf() returns the number of variables initialized with a value , in this case it is 1 because it stores the value of 1 variable .  Therefore scanf() functions returns 1 , which is printed by printf() . Therefore ans is 1 .

Comments

#include <stdio.h>

int main(void) {
    int n;
   printf(“%d”,scanf(“%d”,&n));

    return 0;
}

 

prog.c: In function 'main':
prog.c:5:4: error: stray '\223' in program
    printf(“%d”,scanf(“%d”,&n));
    ^
prog.c:5:12: error: expected expression before '%' token
    printf(“%d”,scanf(“%d”,&n));
            ^
prog.c:5:12: error: stray '\224' in program
prog.c:5:12: error: stray '\223' in program
prog.c:5:12: error: stray '\224' in program
prog.c:4:9: warning: unused variable 'n' [-Wunused-variable]
     int n;
         ^

---

@viv wrong quotes used - " is the correct one.