0 0 votes Consider the following control flow graph The live-variable analysis determines for each point $p$ in a program which variables are live at that point. A live variable v at point p is one where there exists a path from point p to another point q where v is used without v being redefined anywhere along that path.The sets for the livevariable dataflow problem are: use[b] = variables used in block b before any definition def[b] = variables defined in block $b$ and not later killed in $b$ in $[\mathrm{b}]=$ variables live on entry to block $b$ out [b] = variables live on exit from block b The dataflow equations for live variables are in [b] = use[b] $\cup$ (out[b] $-\operatorname{def}[b])$ $\operatorname{out}[b]=U_{s \in \operatorname{Succ}[b]} \operatorname{in}[s]$ What will be the in and out set for basic block B2? in- $\{x, y\}$, out- $\{x, y\}$ in- $\{x, y\}$, out- $\{y, z\}$ in- $\{\mathrm{x}, \mathrm{y}\}$, out- $\{\mathrm{x}, \mathrm{y}, \mathrm{z}\}$ in- $\{x, y, a, b\}$, out- $\{y, z\}$ Compiler Design test-series zeal-test-series compiler-design live-variable-analysis + – nihal_chourasiya 683 views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Hira Thakur commented Dec 12, 2023 reply Follow flag $in(B_2)=(x,y),out(B_2)=(x,y)$?? 0 0 replyShare jach commented Jan 26, 2025 reply Follow flag answer? 0 0 replyShare Please log in or register to add a comment.
0 0 votes Ans is B Abhinav_Mishra answered Sep 8 Abhinav_Mishra comment Share Follow 0 reply Please log in or register to add a comment.