0 0 votes Let $c_{1}, c_{2}, \ldots, c_{n}$ and $z$ be complex numbers such that\[\frac{1}{z-c_{1}}+\frac{1}{z-c_{2}}+\ldots+\frac{1}{z-c_{n}}=0\]Assume that the numbers $c_{1}, c_{2}, \ldots, c_{n}$ are represented in the complex plane by the vertices of a convex $n$-gon $C$. Thenthe number $z$ always lies strictly outside $C$.the number $z$ always lies inside or on $C$.the number $z$ may lie inside or outside $C$ depending on $c_{1}, c_{2}, \ldots, c_{n}$.if $z$ lies inside $C$ then $z$ must be the centroid, i.e., $z=\frac{1}{n} \sum_{k=1}^{n} c_{k}$.None of the above Geometry tifr2025 complex-number geometry + – Shubham Sharma 2 195 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.