2 2 votes $\text{ If P = 3, R = 27, T = 243, then Q + S = ________. }$A. 40B. 80C. 90D. 110 Quantitative Aptitude quantitative-aptitude nptel-quiz one-mark + – Umesh Shelke 929 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 2 2 votes According to the question , Q= 9 , S= 81 Therefore , Q+S= 90 Option C SAMRIDHII09 answered Aug 24, 2025 • selected Aug 24, 2025 by Umesh Shelke SAMRIDHII09 comment Share Follow See all 4 Comments 4 4 Comments reply Amjad. commented Aug 24, 2025 reply Follow flag how did you find the values of Q and S 😀 ? 1 1 replyShare mikasa_ackermann commented Aug 24, 2025 reply Follow flag its nothing bt the square and power $4$ bcz its making a series of $ 3^1 $ , $3^2$ and so on.. 2 2 replyShare SAMRIDHII09 commented Aug 24, 2025 reply Follow flag P = 3 Q = 3x3=9 R= 3x3x3=27 S= 3x3x3x3=81 and so on.. 2 2 replyShare Amjad. commented Aug 24, 2025 reply Follow flag got it , thank you !! 0 0 replyShare Please log in or register to add a comment.
1 1 vote So the correct answer will be Option C i.e 90. Mukul_Pandey answered Sep 18, 2025 Mukul_Pandey comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Alphabetical Order P Q R S T 3 _ 27 _ 243 3 _ 3^3 _ 3^5 so Q+S = 3^2 + 3^4 Q+S = 9 + 81 =>90 Option: C Harshita27 answered Sep 12, 2025 Harshita27 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes So the solution is:P = 3 = 3^1R = 27 = 3^3T = 243 = 3^5Sequence is powers of 3:3^1 = 3, 3^2 = 9, 3^3 = 27, 3^4 = 81, 3^5 = 243So:Q = 3^2 = 9S = 3^4 = 81Q + S = 9 + 81 = 90✅ Answer: C. 90 Smit_Shingala answered Sep 15, 2025 Smit_Shingala comment Share Follow 0 reply Please log in or register to add a comment.