3 3 votes Which of the followings is not a valid property over two fuzzy relations $\tilde{R}$ and $\tilde{S}$ which must be obeyed for performing $\lambda$-cut defuzzifications?$(\tilde{R} \cup \tilde{S})_{\lambda}=\tilde{R}_{\lambda} \cup \tilde{S}_{\lambda}$$(\tilde{R} \cap \tilde{S})_{\lambda}=\tilde{R}_{\lambda} \cap \tilde{S}_{\lambda}$$(\bar{\widetilde{R}})_{\lambda} \neq \bar{R}_{\lambda}$ except when $\lambda=1$For any $\lambda \leq \beta$, where $0 \leq \beta \leq 1$, it is true that $R_{\beta} \subseteq R_{\lambda}$ Artificial Intelligence ugcnetcse-june2025 fuzzy-set mathematical-logic + – Shubham Sharma 2 381 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.