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1 1 vote
Amandeep is in the middle of a bridge of infinite length. He takes the unit step to the right with probability $p$ and to the left with probability $1-p$. Assume that the movements are independent of each other.
Hint: Consider the random variable $X_{i}$ associated with the $i^{\text {th }}$ step defined as:
$$
X_{i}= \begin{cases}1 & \text { if the step of Amandeep is towards the right } \\ -1 & \text { if the step of Amandeep is towards the left }\end{cases}
$$

What is the expected distance between the starting point and end point of Amandeep after $n$ steps?
A. $2 p-1$
B. $n(2 p-1)$
C. $1-2 p$
D. $n(1-2 p)$

1 Answer

1 1 vote
Let us associate a random variable $X_{i}$ with the $i^{\text {th }}$ step.
$$
X_{i}= \begin{cases}1 & \text { if } i^{\text {th }} \text { step of Amandeep is towards the right } \\ -1 & \text { if } i^{t h} \text { step of Amandeep is towards the left }\end{cases}
$$
$E\left(X_{i}\right)=1 \times P\left(X_{i}=1\right)+(-1) \times P\left(X_{i}=-1\right)$
$E\left(X_{i}\right)=1 \times p-1 \times(1-p)=2 p-1$
$S=X_{1}+X_{2}+\ldots+X_{n}$ represents the random distance moved from the starting point after $n$ steps.
Therefore, $E(S)=\sum_{i=1}^{n} E\left(X_{i}\right)=n(2 p-1)$
Hence, expected distance between the starting point and end point of Amandeep after $n$ steps is $n(2 p-1)$
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