1 1 vote Amandeep is in the middle of a bridge of infinite length. He takes the unit step to the right with probability $p$ and to the left with probability $1-p$. Assume that the movements are independent of each other. Hint: Consider the random variable $X_{i}$ associated with the $i^{\text {th }}$ step defined as: $$ X_{i}= \begin{cases}1 & \text { if the step of Amandeep is towards the right } \\ -1 & \text { if the step of Amandeep is towards the left }\end{cases} $$ What is the expected distance between the starting point and end point of Amandeep after $n$ steps? A. $2 p-1$ B. $n(2 p-1)$ C. $1-2 p$ D. $n(1-2 p)$ Probability goclasses statistics goclasses-da-dpp goclasses-da-dpp-day-29 goclasses-statistics-practice-questions + – GO Classes 229 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote Let us associate a random variable $X_{i}$ with the $i^{\text {th }}$ step. $$ X_{i}= \begin{cases}1 & \text { if } i^{\text {th }} \text { step of Amandeep is towards the right } \\ -1 & \text { if } i^{t h} \text { step of Amandeep is towards the left }\end{cases} $$ $E\left(X_{i}\right)=1 \times P\left(X_{i}=1\right)+(-1) \times P\left(X_{i}=-1\right)$ $E\left(X_{i}\right)=1 \times p-1 \times(1-p)=2 p-1$ $S=X_{1}+X_{2}+\ldots+X_{n}$ represents the random distance moved from the starting point after $n$ steps. Therefore, $E(S)=\sum_{i=1}^{n} E\left(X_{i}\right)=n(2 p-1)$ Hence, expected distance between the starting point and end point of Amandeep after $n$ steps is $n(2 p-1)$ GO Classes answered Oct 16, 2025 GO Classes comment Share Follow 0 reply Please log in or register to add a comment.