Suppose that $X, Y$, and $Z$ are three random variables such that $\operatorname{Var}(X)=1, \operatorname{Var}(Y)=4$, $\operatorname{Var}(Z)=8, \operatorname{Cov}(X, Y)=1, \operatorname{Cov}(X, Z)=-1$, and $\operatorname{Cov}(Y, Z)=2$. Determine $\operatorname{Var}(3 X-Y-2 Z+1)$.