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GO Classes DPP | CALCULUS & OPTIMIZATION |MINIMA

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Let the two numbers be $x$ and $y$

$$
x+y=60
$$

objective function from the question will be,

$$
f(x)=x^2(60-x)
$$

For optima $f^{\prime}(x)=0,120 x-3 x^2=0$

$$
x=0,40
$$

Product is minimum when $\mathrm{x}=0$.
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