ISRO2015-32

Question

In a lottery scheduler with 40 tickets, how we will distribute the tickets among 4 processes $P_1, P_2, P_3$ and $P_4$ such that each process gets 10%, 5%, 60% and 25% respectively?

	$P_1$	$P_2$	$P_3$	$P_4$
A	12	4	70	30
B	7	5	20	10
C	4	2	24	10
D	8	5	30	40

Comments

We can easily eliminate option as we are doing part of 40 so all parts sum should also come 40,

Now check all the options only option c has sum 40 all other are more than 40.

Answer 1

Answer is : Option C

40*10 / 100 = 4

40*5 / 100 =2

40*60 / 100 =24

40*25 / 100 = 10

Answer 2

Option C.

Just multiplying the percentages with total no. of tickets.

P1: 40 * 10%=4

P2: 40 * 5%=2

P3 : 40 * 60%=24

P4 : 40 * 25%=10

Answer 3

uNumber of ticket gained by the P1=40x10/100=4

Nmber of ticket gained by the P2=40x5/100=2

Number of ticket gained by the P3=40X60/100=24

Number of ticket gained by the P3=40x25/100=10

Answer 4

25% = 1/4

50% = 1/4 = ( 2 * 25% )

75% = 3/4 = (3 * 25% )

10% 40 = 4

5% = 10% / 2 = 4/2 = 2

60% = 6 * 10% = 6*4 = 24 

25% = 5* 5% = 5 * 2 = 10 or  1/4 * 40 = 10

option C

Answer 5

 

This quection solved by using Options:-

In Option A Sum of all Processes is greater than 40 so it is not possible.

In option B Sum of all Processes is 42 but total tickets is 40 so it is also not possible.

In option c sum of all processes is equal to no of tickets so it is correct ans.