Q1. IN R A1A2 ARE THE CANDIDATE KEY.AND NON KEYS ARE(N-2)
SO NUMBER OF SUPERKEYS =2^(n-2)
Q2 .A1 =CANDIDATE KEY=(N-1) KEYS ARE NON KEYS THESE ARE=A2,A3,A4,A5....AN=>SUPERKEY=2^(N-1)
SIMILARLY FOR A2=SUPERKEYS =2^(N-1)
NOW COMMON ELEMENT IN SET A1 AND A2 IS={A3,A4,A5,A6......AN}=(n-2)keys=THESE ARE THE KEYS WHICH COMBINED WITH BOTH {A1 AND A2} SO REMOVE THIS
==> NUM OF SUPERKEYS=2^(n-1)+2^(n-1)-2^(n-2)
IS THE ANS
YOU CAN PUT IN ANY NUM OF SET TO VERIFIY