11 11 votes An urn contains one red ball and one blue ball. At each step, a ball is picked uniformly at random from the urn, and this ball together with another ball of the same color is put back in the urn. The probability that there are equal number of red and blue balls after two steps is$1 / 4$$1 / 3$$1 / 2$$2 / 3$ Probability gatecse-2026-set1 probability one-mark + – gatecse 2.3k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Jayvijay Chauhan commented May 10 reply Follow flag similar type of problem is asked in 2020 AMC 10B Problems 1 1 replyShare Manglam_Panse commented Aug 20 reply Follow flag @Jayvijay Chauhan I think there are a lot of questions directly taken from wiki. and other sites in discrete mathematics. 0 0 replyShare Please log in or register to add a comment.
Best answer 20 20 votes $\boxed{\text{Answer: B) } \frac{1}{3}}$Tree Diagram https_guru answered Feb 23 • selected Feb 24 by Shaik Masthan https_guru comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote After $2$ draws we will have total of $4$ balls in the urn. In our case we want equal number of Red and Blue balls i.e. $2R \ \&\ 2B$ So one draw should be Blue and another should be Red, the 2 sequence can be $RB$ & $BR$ $\to P(RB) = P(first \ is \ R) \times P(second \ is \ B \ |\ first \ is \ R) = (\frac{1}{2})(\frac{1}{3}) = \frac{1}{6}$ $\to P(BR) = same\ case \ as \ P(RB) = \frac{1}{6}$ Total Probability $P(Equal \ R \ \& \ B) = \frac{1}{6} + \frac{1}{6} = \frac{1}{3}$ Abdul_Kadir answered Feb 23 • moved Feb 24 by Misbah Ghaya Abdul_Kadir comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes . Meticulous_March answered Apr 1 Meticulous_March comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Answer is 1/3 As explained in below image dev212827 answered Apr 5 dev212827 comment Share Follow 0 reply Please log in or register to add a comment.