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An urn contains one red ball and one blue ball. At each step, a ball is picked uniformly at random from the urn, and this ball together with another ball of the same color is put back in the urn. The probability that there are equal number of red and blue balls after two steps is

  1. $1 / 4$
  2. $1 / 3$
  3. $1 / 2$
  4. $2 / 3$

4 Answers

1 1 vote
After $2$ draws we will have total of $4$ balls in the urn. In our case we want equal number of Red and Blue balls i.e. $2R \ \&\ 2B$
 

So one draw should be Blue and another should be Red, the 2 sequence can be $RB$ & $BR$

$\to P(RB) = P(first \ is \ R) \times P(second \ is \ B \ |\ first \ is \ R) = (\frac{1}{2})(\frac{1}{3}) = \frac{1}{6}$

$\to P(BR) = same\ case \ as \ P(RB) = \frac{1}{6}$

Total Probability  $P(Equal \ R \ \& \ B) = \frac{1}{6} + \frac{1}{6} = \frac{1}{3}$
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