C -Programming

Question

Answer 1

Answer is option D]

for a given code, Out put will be : 012345678910111213141516171819

Option A will result in : 012345678910111213141515151515151515....

Option B will result in : 0123456789101112131415  

Option C : x variable has to be initialized first.

Option D : 012345678910111213141516171819

Hence the answer.

The continue skips the statements after it. And continues with next iteration.

Comments

how 15 is comparing in each options?

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answer edited..

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ok yes A and B both will cause compilation error rt?

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@lord Krishna can you explain  what does this line is doing in the for loop count<<j ; and what is the role of continue statement here?

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we use cout<<j in c++ to print values of j in the terminal. it is here doing the same thing ..

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@kapil i thought it would be something related to left shift or right shift . then what about the continue statement. if we don't use  this statement would it give us a different o/p.

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sir, continue will directly go to the increment condition and then test it and then print

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@kapil you mean next iteration rt ? so to next increment condition we can go without it so what is the significance of using it here ?

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yes, if we dont use it , result will be same.

if there were statements after continue they wont execute.

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@kapil lordkrishna has written a line at the end of his solution can you tell me something about it ? if you know it

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sir, what continue does? it directly takes the control from current execution statement to increment condition . after incrementing , it tests it and then goes again in the loop...

so , now in this process, if there were any statements after continue will be skipped

take example of variable named k, and we are decrementing k after continue, so because of this continue , it will be skipped.

hence , continue skips some statements inside the loop

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hey @shekhar chauhan , The continue skips the statements after it. And continues with next iteration.