A recognizer $M$ for $L$ satisfies
$w\in L\iff M\ \mathrm{accepts}\ w$.
A is true. If $M$ rejects $w$, it did not accept $w$.
$\therefore w\notin L$
B is false. For a nonmember, a recognizer is allowed to either $\boxed{\mathrm{reject}}$ or $\boxed{\mathrm{loop\ forever}}$.
So $w\notin L$ does not force rejection.
C is true. If $w\in L$, a recognizer for $L$ must eventually accept $w$. If $M$ loops on that member, $M$ cannot be a recognizer for $L$.
D is false. It only proves that this particular machine $M$ does not recognize $L$. Some other TM could still recognize $L$.