Given,receiver clock is 0.1% faster than sender clock.
At 1 Mbps bits send by sender = 1000000
receiver clock is 0.1% faster than sender clock so Extra bits received by receiver = 1000000 * $\frac{0.1}{100}$
=1000 bits
Total bits received by received= 1001000 bits
Extra bit per second received by receiver= 1000 bps
Hence,Option(C)1000 bps is the correct choice.