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2 Answers

Best answer
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Take L as  a*b*

a*b*+a^nb^n = a*b*

Where R HERE IS a^nb^n is cfl 

Now take L as £* 

a*b*+£*=£*     

where £* is ( sigma*)

Here R is £* which is regular so 

R MAY MAY OR MAY NOT REGULAR 

b) option ans 

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Option A. Must be Regular. Union of 2 regular language is regular. We cannot assure regularity in case of other options.

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