1 1 vote If L is a regular Language and R is any language such that L+R is regular,then R is a)Must be regular b)May or may not be regular c)Must be non regular language d)Must be CFL Theory of Computation theory-of-computation regular-language + – resilientknight 735 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 3 3 votes Take L as a*b* a*b*+a^nb^n = a*b* Where R HERE IS a^nb^n is cfl Now take L as £* a*b*+£*=£* where £* is ( sigma*) Here R is £* which is regular so R MAY MAY OR MAY NOT REGULAR b) option ans focus _GATE answered Aug 3, 2016 • selected Aug 3, 2016 by resilientknight focus _GATE comment Share Follow See all 2 Comments 2 2 Comments reply resilientknight commented Aug 3, 2016 reply Follow flag awesome,thank you, another question though,is it possible to make union of 2 non regular languages = sigma *(because we are missing out all the regular ones as they are closed under union)? 1 1 replyShare focus _GATE commented Aug 3, 2016 reply Follow flag Yes it is possible . a^nb^n ∪( a^nb^n )'= €* Where (a^nb^n)' is complement of a^nb^n! 1 1 replyShare Please log in or register to add a comment.
0 0 votes Option A. Must be Regular. Union of 2 regular language is regular. We cannot assure regularity in case of other options. Manu Madhavan answered Aug 3, 2016 Manu Madhavan comment Share Follow See 1 comment 1 1 comment reply resilientknight commented Aug 3, 2016 reply Follow flag nope this is not the answer given, so a bit confused. 0 0 replyShare Please log in or register to add a comment.