1 votes 1 votes a real n*n matrix aij =i if i = j , otherwise 0 the determinant of all n eigen values of A is a) n(n+1)/2 b) n(n-1)/2 c) n(n+1)(2n+1)/6 d) factorial(n) my ans is d but the ans given is a. Is it correct? qwertyui asked Aug 15, 2016 qwertyui 854 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments Habibkhan commented Oct 4, 2016 reply Follow Share It is not like that.The product of eigen values of matrix A = |A| There is nothing like determinant of eigen value.It is meaningless. 0 votes 0 votes Prashant. commented Oct 4, 2016 reply Follow Share i think quetion is for determinant of matrix A = which is product of eigen value of matrix A = n! 0 votes 0 votes Habibkhan commented Oct 4, 2016 reply Follow Share Yes in that case it will be n! since it is a diagonal matrix , hence product of eigen values = determinant of matrix A = product of diagonal values(since they are eigen values themselves) which is hence given by, 1.2.3......n = n! 0 votes 0 votes Please log in or register to add a comment.