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What will be the output of the program assuming that the array begins at the location 1002 and size of an integer is 4 bytes?
#include<stdio.h>

int main()
{
    int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 };
    printf("%u, %u, %u\n", a[0]+1, *(a[0]+1), *(*(a+0)+1));
    return 0;
}
    A.    448, 4, 4
    B.    520, 2, 2
    C.    1006, 2, 2
    D.    Error

1 Answer

0 0 votes
C should be the answer as the a[0] + 1 is the base address + 1 ie 1002 + 4 = 1006.
other two are the same is writting the a[0][1].
a[0] can be written as *a.
a[5] can be written as *(a + 5 ).
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