2 2 votes Am I Correct? Suppose we have 3-bit sequence number and acknowlwdgements are piggybacked. Then channel utilization is A. Stop and Wait =Transmission time/(2*transmission time + 2*propagation time) B.GBN =7*transmission time/(2*transmission time + 2*propagation time) C.SR =4*transmission time/(2*transmission time + 2*propagation time) Okay, here is the full question in which i applied above formulas:: Frames of 1000 bits are sent over a 1Mbps link between earth and moon whose propagation delay is 270msec. Headers are very short and acknowledgments are always piggybacked on to data frames. Three bit sequence numbers are used. What is the maximum channel achievable channel utilization in A.Stop and wait B. GBN C.SR Computer Networks computer-networks sliding-window + – Shivam Chauhan 1.4k views answer comment Share Follow Print See all 5 Comments 5 5 Comments reply Show 2 previous comments Arjun commented Sep 13, 2016 reply Follow flag For that both sender and receiver must be sending data continuously. I mean no such data mentioned in your question. –2 –2 replyShare Shivam Chauhan commented Sep 14, 2016 reply Follow flag Please check now. I have edited the question. 0 0 replyShare ankyAS commented Jan 14, 2017 reply Follow flag if u have taken the transmission time in Numerator then u must do the same for the Denominator. 0 0 replyShare Please log in or register to add a comment.
0 0 votes @Shivam. Why are you taking 2*transmission time in the remainder? It must be simply transmission time. Sushant Gokhale answered Sep 30, 2016 Sushant Gokhale comment Share Follow See all 3 Comments 3 3 Comments reply Shivam Chauhan commented Sep 30, 2016 reply Follow flag @Sushant+Gokhale because acknowledgments are piggybacked thus we have to consider transmission time of acknowledgment also 0 0 replyShare Sushant Gokhale commented Oct 1, 2016 reply Follow flag Good point :) 0 0 replyShare Shivam Chauhan commented Oct 1, 2016 reply Follow flag @Sushant+Gokhale I have edited all the formulas. @Arjun sir please verify above formulas 0 0 replyShare Please log in or register to add a comment.