13 votes 13 votes Given Set $A= {2, 3, 4, 5}$ and Set $B= { 11, 12, 13, 14, 15}$, two numbers are randomly selected, one from each set. What is the probability that the sum of the two numbers equals $16$? $0.20$ $0.25$ $0.30$ $0.33$ Quantitative Aptitude gatecse-2015-set1 quantitative-aptitude probability normal + – makhdoom ghaya asked Feb 11, 2015 • edited Jun 7, 2018 by Milicevic3306 makhdoom ghaya 7.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 17 votes 17 votes option A because total combinations are $5\times 4=20$ and out of $20$ we have only $4$ combinations which have sum $16$ $2,14$ $3.13$ $4.12$ $5,11$ Anoop Sonkar answered Feb 12, 2015 • edited Jun 8, 2018 by Arjun Anoop Sonkar comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments jatin khachane 1 commented Nov 28, 2018 reply Follow Share @Lakshman Patel RJIT (2,14) (14,2) (3.13) (13,3) (4.12) (12,4) (5,11) (11,5) This will also be correct 8 / 40 ==>0.2 4 votes 4 votes G Phalkey commented Sep 29, 2019 reply Follow Share yes ,set does not contain duplicate 0 votes 0 votes nocturnal123 commented Jun 28, 2021 reply Follow Share Case: Two dices are thrown, what is the probability that sum is 5. Then why we consider (2,3) and (3,2) as different cases ! I think @Lakshman Patel RJIT, query is legitimate and @jatin khachane 1’s solution seems suitable. 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes option A probability =Number of favorable case/total case The favorable cases are:- 2,14 3.13 4.12 5,11 4C1=4 total case =A number selected from set A * A number selected from set B 4C1*5C1=20 probability =Number of favorable case/total case=4/20=0.20 learner_geek answered Jan 28, 2018 learner_geek comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes After choosing an element from A, there is only one element in B out of 5 elements that makes sum 16. So, 1/5 = 0.2 Skan answered Feb 1, 2018 Skan comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Solution: A The total number of pairs possible is 20(with 1 element from A and 1 element from B). The pairs which sum to 16 are 4nos, that are (2,14)(3,13)(4,12)(5,11). So 4/20 =0.20 Naseer answered Feb 1, 2020 Naseer comment Share Follow See all 0 reply Please log in or register to add a comment.