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Is there SR conflict in SLR(1) ?

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It is not SLR(1). Shift-reduce conflict in I-6 over terminal t. [Q -> . ] will be in Follow(Q)={t, $}. There is shift entry on t in I-6.
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its not SLR(1) while finding follow for S and Q, we got multiples entries inthe $ and t cell so its not SLR(1)..
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