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A packet of 10 bulbs is known to include 2 bulbs that are defective. If 4 bulbs are chosen randomly and tested, probability for finding not more than 1 defective bulb is____

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Total ways to choose 4 out of 10 is 10C4

no defective--->8C4

1 defective---->2C1*8C3

so probability=(8C4 + 2C1*8C3)/10C4=0.86666667
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