0 0 votes Okay , So R is RE , L is Regular language. 1) Definitely true , RE not closed under complement. 2) Regular union Non regular language ? Could be possbile. Not too sure. 3) L interesection R' is not RE ? Not sure 4) ?? Not sure 5) ?? Not sure Can you help with these ? Theory of Computation decidability theory-of-computation regular-language + – vishal8492 623 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes I think none of the option is correct. A. RE are not closed under Complement operation. So it is not evern Turing Recognizable B and C and E options. Since RE' is not even Turing Recognizable and we don't know anything about those languages. So we cannot comment on any operation on those Languages. Threrefore all are False. D. LUR is Recursive Enumerable but not Recursive. To find the Union Move L to upper Level in Chomsky Hierarchy to RE languages. Since RE are closed under Union. Therefore LUR is RE and not Recursive. So this statement is also False. Mehak Sharma 1 answered Dec 17, 2016 Mehak Sharma 1 comment Share Follow 0 reply Please log in or register to add a comment.