Question

Suppose a line with a length of 100km runs at T1 data rate. Then how much data can be fit in the line, if speed of the line is ⅔ rd of the speed of light? Note: T1 data rate is well known to represent 1.544Mbps with each frame of size 193 bits.

1.   642 B
2.   96.5 B
3.   772 B
4.   331 B

Answer 1

Total number of bits can be filled till propagation delay = $1.544Mb*P_{delay}$ bits.

Where $P_{delay} = 5*10^{-4}$

$\rightarrow$ Total bits filled = 772 bits = 96.5 bytes.

Comments

If transfer can take place only on one direction when receiver would send acknowledgement ?

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i got ur point..but how to decide then the delay taken should be RTT or just propagation time..?

and dint get ur piggybanking logic..

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In data packing, if not mentioned two way data transfer, we can only assume for one way transfer, hence only Tp. Warning : I don't have reference. ;)