2 votes 2 votes Suppose a line with a length of 100km runs at T1 data rate. Then how much data can be fit in the line, if speed of the line is ⅔ rd of the speed of light? Note: T1 data rate is well known to represent 1.544Mbps with each frame of size 193 bits. 642 B 96.5 B 772 B 331 B Computer Networks computer-networks + – Akriti sood asked Jan 2, 2017 Akriti sood 535 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes Total number of bits can be filled till propagation delay = $1.544Mb*P_{delay}$ bits. Where $P_{delay} = 5*10^{-4}$ $\rightarrow$ Total bits filled = 772 bits = 96.5 bytes. Aghori answered Jan 2, 2017 • selected Jan 3, 2017 by Akriti sood Aghori comment Share Follow See all 6 Comments See all 6 6 Comments reply Akriti sood commented Jan 3, 2017 reply Follow Share dun you think that delay should be 2*propagation delay?? because we can fill the line till that duration.. 0 votes 0 votes Aghori commented Jan 3, 2017 reply Follow Share I think since it is not mentioned the transfer is piggybacked we need to wait for acknowledgement first once we send many frames in one go. 0 votes 0 votes Akriti sood commented Jan 3, 2017 reply Follow Share how it has to do with piggbanking..??total cycle time is transmission time + round trip time..to utitlize fully,we can sedn tht much data in one go 0 votes 0 votes Aghori commented Jan 3, 2017 reply Follow Share If transfer can take place only on one direction when receiver would send acknowledgement ? 0 votes 0 votes Akriti sood commented Jan 3, 2017 reply Follow Share i got ur point..but how to decide then the delay taken should be RTT or just propagation time..? and dint get ur piggybanking logic.. 0 votes 0 votes Aghori commented Jan 3, 2017 reply Follow Share In data packing, if not mentioned two way data transfer, we can only assume for one way transfer, hence only Tp. Warning : I don't have reference. ;) 2 votes 2 votes Please log in or register to add a comment.