Login
Register
@
Dark Mode
Profile
Edit my Profile
Messages
My favorites
Register
Activity
Q&A
Questions
Unanswered
Tags
Subjects
Users
Ask
Previous Years
Blogs
New Blog
Exams
Dark Mode
Recent questions tagged binomial-distribution
0
votes
0
answers
1
Best Open Video Playlist for Binomial Distributions Topic | Probability
Please list out the best free available video playlist for Binomial Distributions Topic from Probability as an answer here (only one playlist per answer). We'll then select the best playlist and add to GO classroom video lists ... ones are more likely to be selected as best. For the full list of selected videos please see here
makhdoom ghaya
asked
in
Study Resources
Aug 15, 2022
by
makhdoom ghaya
42
views
missing-videos
go-classroom
free-videos
video-links
binomial-distribution
0
votes
0
answers
2
MadeEasy Test Series: Probability
How to get the idea that we have to use Binomial distribution or Hypergeometric Distribution. I know that if the probability is not changing(i.e with replacement) then we go Binomial otherwise Hypergeometric. But in question, it is not indicating ... So is there any by default approach that we have to use Binomial if nothing is a mention about a replacement.
junaid ahmad
asked
in
Probability
Jan 9, 2019
by
junaid ahmad
335
views
made-easy-test-series
probability
binomial-distribution
0
votes
0
answers
3
Binomial distribution
Is there any relation between MEAN, VARIANCE and MODE for binomial distribution? Let, Mean = 8, variance = 6 for any binomial distribution. np = 8 and npq = 6 => q=$3/4$, p=$1/4$ Now is there any relation to find value of MODE ?
shreyansh jain
asked
in
Mathematical Logic
Dec 18, 2018
by
shreyansh jain
455
views
binomial-distribution
1
vote
1
answer
4
Hk Dass
In a binomial distribution the sum and the product of mean and variance are $\Large \frac{25}{3}$ and $\Large \frac{50}{3}$ respectively. The distribution is _______. Note : I've not included the options to avoid KBC in comments
Mk Utkarsh
asked
in
Probability
Aug 31, 2018
by
Mk Utkarsh
801
views
binomial-distribution
probability
1
vote
1
answer
5
Probability
We have applied Bernoulli equation to solve the answer. But, why the answer isn't C(90,5)÷C(100,5)?
Arjun045
asked
in
Probability
Aug 9, 2018
by
Arjun045
437
views
binomial-distribution
probability
7
votes
2
answers
6
TIFR CSE 2018 | Part A | Question: 10
Let $C$ be a biased coin such that the probability of a head turning up is $p.$ Let $p_n$ denote the probability that an odd number of heads occurs after $n$ tosses for $n \in \{0,1,2,\ldots \},$ ... $p_{n}=1 \text{ if } n \text{ is odd and } 0 \text{ otherwise}.$
Arjun
asked
in
Probability
Dec 10, 2017
by
Arjun
1.5k
views
tifr2018
probability
binomial-distribution
1
vote
1
answer
7
$a_n = 4^n + 6^n$
If $a_n = 4^n + 6^n$ Find the value of $a_{40} \text { mod } 25$
dd
asked
in
Set Theory & Algebra
May 19, 2017
by
dd
318
views
binomial-distribution
3
votes
1
answer
8
Hashing+Probaility
Rahul Jain25
asked
in
DS
Oct 8, 2016
by
Rahul Jain25
543
views
hashing
probability
uniform-hashing
binomial-distribution
17
votes
5
answers
9
TIFR CSE 2013 | Part A | Question: 14
An unbiased die is thrown $n$ times. The probability that the product of numbers would be even is $\dfrac{1}{(2n)}$ $\dfrac{1}{[(6n)!]}$ $1 - 6^{-n}$ $6^{-n}$ None of the above
makhdoom ghaya
asked
in
Probability
Nov 4, 2015
by
makhdoom ghaya
1.3k
views
tifr2013
probability
binomial-distribution
10
votes
1
answer
10
TIFR CSE 2013 | Part A | Question: 4
A biased coin is tossed repeatedly. Assume that the outcomes of different tosses are independent and probability of heads is $\dfrac{2}{3}$ in each toss. What is the probability of obtaining an even number of heads in $5$ tosses, zero being treated as an even ... $\left(\dfrac{124}{243}\right)$ $\left(\dfrac{125}{243}\right)$ $\left(\dfrac{128}{243}\right)$
makhdoom ghaya
asked
in
Probability
Nov 4, 2015
by
makhdoom ghaya
1.2k
views
tifr2013
probability
binomial-distribution
9
votes
6
answers
11
TIFR CSE 2012 | Part A | Question: 17
A spider is at the bottom of a cliff, and is $n$ inches from the top. Every step it takes brings it one inch closer to the top with probability $1/3$, and one inch away from the top with probability $2/3$, unless it is at the bottom in which ... $n$? It will never reach the top. Linear in $n$. Polynomial in $n$. Exponential in $n$. Double exponential in $n$.
makhdoom ghaya
asked
in
Probability
Oct 30, 2015
by
makhdoom ghaya
1.8k
views
tifr2012
probability
binomial-distribution
13
votes
4
answers
12
TIFR CSE 2011 | Part A | Question: 3
The probability of three consecutive heads in four tosses of a fair coin is $\left(\dfrac{1}{4}\right)$ $\left(\dfrac{1}{8}\right)$ $\left(\dfrac{1}{16}\right)$ $\left(\dfrac{3}{16}\right)$ None of the above
makhdoom ghaya
asked
in
Probability
Oct 17, 2015
by
makhdoom ghaya
2.3k
views
tifr2011
probability
binomial-distribution
23
votes
6
answers
13
TIFR CSE 2010 | Part B | Question: 38
Suppose three coins are lying on a table, two of them with heads facing up and one with tails facing up. One coin is chosen at random and flipped. What is the probability that after the flip the majority of the coins(i.e., at least two of them) will have heads facing up ... $\left(\frac{1}{4}+\frac{1}{8}\right)$ $\left(\frac{2}{3}\right)$
makhdoom ghaya
asked
in
Probability
Oct 11, 2015
by
makhdoom ghaya
2.9k
views
tifr2010
probability
binomial-distribution
12
votes
2
answers
14
TIFR CSE 2010 | Part A | Question: 6
Given 10 tosses of a coin with probability of head = .$4$ = ($1$ - the probability of tail), the probability of at least one head is? $(.4)^{10}$ $1 - (.4)^{10}$ $1 - (.6)^{10}$ $(.6)^{10}$ $10(.4) (.6)^{9}$
makhdoom ghaya
asked
in
Probability
Oct 2, 2015
by
makhdoom ghaya
1.7k
views
tifr2010
probability
binomial-distribution
62
votes
7
answers
15
GATE IT 2005 | Question: 32
An unbiased coin is tossed repeatedly until the outcome of two successive tosses is the same. Assuming that the trials are independent, the expected number of tosses is $3$ $4$ $5$ $6$
Ishrat Jahan
asked
in
Probability
Nov 3, 2014
by
Ishrat Jahan
18.2k
views
gateit-2005
probability
binomial-distribution
expectation
normal
36
votes
4
answers
16
GATE IT 2006 | Question: 22
When a coin is tossed, the probability of getting a Head is $p, 0 < p < 1$. Let $N$ be the random variable denoting the number of tosses till the first Head appears, including the toss where the Head appears. Assuming that successive tosses are independent, the expected value of $N$ is $\dfrac{1}{p}$ $\dfrac{1}{(1 - p)}$ $\dfrac{1}{p^{2}}$ $\dfrac{1}{(1 - p^{2})}$
Ishrat Jahan
asked
in
Probability
Oct 31, 2014
by
Ishrat Jahan
7.1k
views
gateit-2006
probability
binomial-distribution
expectation
normal
16
votes
3
answers
17
GATE IT 2007 | Question: 1
Suppose there are two coins. The first coin gives heads with probability $\dfrac{5}{8}$ when tossed, while the second coin gives heads with probability $\dfrac{1}{4}.$ One of the two coins is picked up at random with equal probability and tossed. What is the probability of ... $\left(\dfrac{1}{2}\right)$ $\left(\dfrac{7}{16}\right)$ $\left(\dfrac{5}{32}\right)$
Ishrat Jahan
asked
in
Probability
Oct 30, 2014
by
Ishrat Jahan
2.8k
views
gateit-2007
probability
normal
binomial-distribution
25
votes
9
answers
18
GATE CSE 2005 | Question: 52
A random bit string of length n is constructed by tossing a fair coin n times and setting a bit to 0 or 1 depending on outcomes head and tail, respectively. The probability that two such randomly generated strings are not identical is: $\frac{1}{2^n}$ $1 - \frac{1}{n}$ $\frac{1}{n!}$ $1 - \frac{1}{2^n}$
gatecse
asked
in
Probability
Sep 21, 2014
by
gatecse
6.1k
views
gatecse-2005
probability
binomial-distribution
easy
32
votes
7
answers
19
GATE CSE 2006 | Question: 21
For each element in a set of size $2n$, an unbiased coin is tossed. The $2n$ coin tosses are independent. An element is chosen if the corresponding coin toss was a head. The probability that exactly $n$ elements are chosen is $\frac{^{2n}\mathrm{C}_n}{4^n}$ $\frac{^{2n}\mathrm{C}_n}{2^n}$ $\frac{1}{^{2n}\mathrm{C}_n}$ $\frac{1}{2}$
Rucha Shelke
asked
in
Probability
Sep 17, 2014
by
Rucha Shelke
6.4k
views
gatecse-2006
probability
binomial-distribution
normal
17
votes
5
answers
20
GATE CSE 2002 | Question: 2.16
Four fair coins are tossed simultaneously. The probability that at least one head and one tail turn up is $\frac{1}{16}$ $\frac{1}{8}$ $\frac{7}{8}$ $\frac{15}{16}$
Kathleen
asked
in
Probability
Sep 16, 2014
by
Kathleen
9.0k
views
gatecse-2002
probability
easy
binomial-distribution
To see more, click for the
full list of questions
or
popular tags
.
Subscribe to GATE CSE 2023 Test Series
Subscribe to GO Classes for GATE CSE 2023
Quick search syntax
tags
tag:apple
author
user:martin
title
title:apple
content
content:apple
exclude
-tag:apple
force match
+apple
views
views:100
score
score:10
answers
answers:2
is accepted
isaccepted:true
is closed
isclosed:true
Recent Posts
Central Pollution Control Board CPCB Various Post Recruitment 2023
MP Rajya Sahkari Apex Bank Various Post Recruitment 2023
NITIE MUMBAI throgh GATE
PGCIL recruitment 2023 – Apply Online For 138 Posts through GATE
Admission guidance for GATE CSE 2023
Subjects
All categories
General Aptitude
(2.6k)
Engineering Mathematics
(9.4k)
Digital Logic
(3.3k)
Programming and DS
(5.9k)
Algorithms
(4.6k)
Theory of Computation
(6.7k)
Compiler Design
(2.3k)
Operating System
(5.0k)
Databases
(4.6k)
CO and Architecture
(3.8k)
Computer Networks
(4.7k)
Non GATE
(1.3k)
Others
(2.5k)
Admissions
(655)
Exam Queries
(847)
Tier 1 Placement Questions
(17)
Job Queries
(77)
Projects
(9)
Unknown Category
(866)
Recent questions tagged binomial-distribution
Recent Blog Comments
Please see the updated link.
Unfortunately there won't be a hardcopy coming...
this book is not available on amazon now, i want...
Yes
Hi! @AnkitMazumder14 bhaiya,Is python...