Recent questions tagged binomial-distribution

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1

MadeEasy Test Series: Probability
How to get the idea that we have to use Binomial distribution or Hypergeometric Distribution. I know that if the probability is not changing(i.e with replacement) then we go Binomial otherwise Hypergeometric. But in question, it is not indicating ... So is there any by default approach that we have to use Binomial if nothing is a mention about a replacement.

junaid ahmad asked in Mathematical Logic Jan 9, 2019

by junaid ahmad

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2

Binomial distribution
Is there any relation between MEAN, VARIANCE and MODE for binomial distribution? Let, Mean = 8, variance = 6 for any binomial distribution. np = 8 and npq = 6 => q=$3/4$, p=$1/4$ Now is there any relation to find value of MODE ?

shreyansh jain asked in Mathematical Logic Dec 18, 2018

by shreyansh jain

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0 votes

1 answer

3

Hk Dass
In a binomial distribution the sum and the product of mean and variance are $\Large \frac{25}{3}$ and $\Large \frac{50}{3}$ respectively. The distribution is _______. Note : I've not included the options to avoid KBC in comments

Mk Utkarsh asked in Probability Aug 31, 2018

483 views

0 votes

1 answer

4

Probability
We have applied Bernoulli equation to solve the answer. But, why the answer isn't C(90,5)÷C(100,5)?

Arjun045 asked in Probability Aug 9, 2018

214 views

1 vote

1 answer

5

$a_n = 4^n + 6^n$
If $a_n = 4^n + 6^n$ Find the value of $a_{40} \text { mod } 25$

dd asked in Set Theory & Algebra May 19, 2017

by dd

226 views

3 votes

1 answer

6

Hashing+Probaility

Rahul Jain25 asked in DS Oct 8, 2016

by Rahul Jain25

383 views

11 votes

4 answers

7

TIFR2011-A-3
The probability of three consecutive heads in four tosses of a fair coin is $\left(\dfrac{1}{4}\right)$ $\left(\dfrac{1}{8}\right)$ $\left(\dfrac{1}{16}\right)$ $\left(\dfrac{3}{16}\right)$ None of the above

makhdoom ghaya asked in Probability Oct 17, 2015

by makhdoom ghaya

1.6k views

21 votes

6 answers

8

TIFR2010-B-38
Suppose three coins are lying on a table, two of them with heads facing up and one with tails facing up. One coin is chosen at random and flipped. What is the probability that after the flip the majority of the coins(i.e., at least two of them) will have heads facing up? ... $\left(\frac{1}{4}\right)$ $\left(\frac{1}{4}+\frac{1}{8}\right)$ $\left(\frac{2}{3}\right)$

makhdoom ghaya asked in Probability Oct 11, 2015

by makhdoom ghaya

2.1k views

10 votes

2 answers

9

TIFR2010-A-6
Given 10 tosses of a coin with probability of head = .$4$ = ($1$ - the probability of tail), the probability of at least one head is? $(.4)^{10}$ $1 - (.4)^{10}$ $1 - (.6)^{10}$ $(.6)^{10}$ $10(.4) (.6)^{9}$

makhdoom ghaya asked in Probability Oct 2, 2015

by makhdoom ghaya

1.3k views

50 votes

6 answers

10

GATE IT 2005 | Question: 32
An unbiased coin is tossed repeatedly until the outcome of two successive tosses is the same. Assuming that the trials are independent, the expected number of tosses is $3$ $4$ $5$ $6$

Ishrat Jahan asked in Probability Nov 3, 2014

by Ishrat Jahan

13.8k views

28 votes

4 answers

11

GATE IT 2006 | Question: 22
When a coin is tossed, the probability of getting a Head is $p, 0 < p < 1$. Let $N$ be the random variable denoting the number of tosses till the first Head appears, including the toss where the Head appears. Assuming that successive tosses are independent, the expected value of $N$ is $\dfrac{1}{p}$ $\dfrac{1}{(1 - p)}$ $\dfrac{1}{p^{2}}$ $\dfrac{1}{(1 - p^{2})}$

Ishrat Jahan asked in Probability Oct 31, 2014

by Ishrat Jahan

5.3k views

11 votes

3 answers

12

GATE IT 2007 | Question: 1
Suppose there are two coins. The first coin gives heads with probability $\dfrac{5}{8}$ when tossed, while the second coin gives heads with probability $\dfrac{1}{4}.$ One of the two coins is picked up at random with equal probability and tossed. What is the probability of ... $\left(\dfrac{1}{2}\right)$ $\left(\dfrac{7}{16}\right)$ $\left(\dfrac{5}{32}\right)$

Ishrat Jahan asked in Probability Oct 30, 2014

by Ishrat Jahan

1.9k views

18 votes

3 answers

13

GATE CSE 2011 | Question: 3
If two fair coins are flipped and at least one of the outcomes is known to be a head, what is the probability that both outcomes are heads? $\left(\dfrac{1}{3}\right)$ $\left(\dfrac{1}{4}\right)$ $\left(\dfrac{1}{2}\right)$ $\left(\dfrac{2}{3}\right)$

jothee asked in Probability Sep 29, 2014

by jothee

5.1k views

20 votes

9 answers

14

GATE CSE 2005 | Question: 52
A random bit string of length n is constructed by tossing a fair coin n times and setting a bit to 0 or 1 depending on outcomes head and tail, respectively. The probability that two such randomly generated strings are not identical is: $\frac{1}{2^n}$ $1 - \frac{1}{n}$ $\frac{1}{n!}$ $1 - \frac{1}{2^n}$

gatecse asked in Probability Sep 21, 2014

4.5k views

24 votes

7 answers

15

GATE CSE 2006 | Question: 21
For each element in a set of size $2n$, an unbiased coin is tossed. The $2n$ coin tosses are independent. An element is chosen if the corresponding coin toss was a head. The probability that exactly $n$ elements are chosen is $\frac{^{2n}\mathrm{C}_n}{4^n}$ $\frac{^{2n}\mathrm{C}_n}{2^n}$ $\frac{1}{^{2n}\mathrm{C}_n}$ $\frac{1}{2}$

Rucha Shelke asked in Probability Sep 17, 2014

by Rucha Shelke

4.9k views

12 votes

5 answers

16

GATE CSE 2002 | Question: 2.16
Four fair coins are tossed simultaneously. The probability that at least one head and one tail turn up is $\frac{1}{16}$ $\frac{1}{8}$ $\frac{7}{8}$ $\frac{15}{16}$

Kathleen asked in Probability Sep 16, 2014

7k views

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