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Recent questions tagged graycode
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#digital logic self doubt
Is there any formula to directly calculate the number of GRAY CODES possible? say like for 1 bit number of gray code possible = ... say like for 2 bits number of gray code possible = .... say like for 3 bist number of gray code possible = ....
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Degital logic BCD to Excess 3
The once compliment of the given BCD excess 3 code is 9's compliment of the given BCD in the excess 3 form because of this Excess3 code is named as self complimentry code.. Please elaborate and well explain above sentence
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Aug 24, 2017
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Digital Logic
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air1ankit
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madeeasybooklet
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TIFR2017B8
For any natural number $n$, an ordering of all binary strings of length $n$ is a Gray code if it starts with $0^n$, and any successive strings in the ordering differ in exactly one bit (the first and last string must also differ by one bit). Thus, for ... code, if two strings are separated by $k$ other strings in the ordering, then they must differ in exactly $k$ bits none of the above
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Dec 23, 2016
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Digital Logic
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jothee
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tifr2017
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Mux & Gray Code
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Jan 5, 2016
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Digital Logic
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Himanshu1
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digitallogic
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Question on gray code
I read somewhere that gray code is selfcomplementing but I couldn't find any explanation for that. Please tell if anyone has some idea about it.
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Jan 4, 2016
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Digital Logic
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shikharV
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digitallogic
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GATE200640
Consider numbers represented in 4bit Gray code. Let $ h_{3}h_{2}h_{1}h_{0}$ be the Gray code representation of a number $n$ and let $ g_{3}g_{2}g_{1}g_{0}$ be the Gray code of $ (n+1)(modulo 16)$ value of the number. Which one of the following functions is correct? $ g_{0}(h_{3}h_{2}h_{1}h_ ... {0})=\sum (2, 4,5,6,7,12,13,15) $ $ g_{3}(h_{3}h_{2}h_{1}h_{0})=\sum (0,1,6,7,10,11,12,13) $
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Sep 26, 2014
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Rucha Shelke
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