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#plz explain??

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In a boxing tournament $2^{n}$ equally skilled players $P_{1}, P_{2}, P_{3} \ldots \ldots \ldots . P_{2^{n}}$, are participating In each round players are divided in pairs at random and winner from each pair moves in next round if P5 reaches the semifinals then what is the probability that $P_{1}$ wins the toumament?
$1\left(\frac{1}{2}\right)^{\log n}$
2. $\frac{2^{\operatorname{son} x}-1}{2^{x}-1}$
3) $\frac{3}{4} \times \frac{1}{2^{n}-1}$
Correct Answer 111\% answered eorrectly
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0154
$8-21-8217$

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