1 1 vote Which of the following statements is NOT true? $DFA$ makes precisely one transition for an input. $NFA$ can make more than one transition for an input. On a given string ‘w’, $DFA$ terminates exactly in one state. To check if the input is accepted by an $NFA$, it does not make more than one transition for an input symbol from each state. GATE tbb-mockgate-3 theory-of-computation finite-automata + – Bikram 679 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 2 2 votes A. DFA makes precisely one transition for an input symbol from each state. The statement is correct. The statement is implied from DFA definition B. NFA makes more than one transition for an input symbol from each state. To check if the string is accepted by NFA we need to check more than one path labeled w and select one which terminates at a final state. The statement is correct. C. The statement is true. DFA has a unique transition for a give input symbol w and state q to other state. This suggests that on a given string w, DFA terminates in one and only state. D. The statement is false. Read explanation about statement 2. Bikram answered Feb 9, 2017 • selected Feb 10, 2017 by Bikram Bikram comment Share Follow See all 2 Comments 2 2 Comments reply Arjun commented Feb 9, 2017 reply Follow flag D statement is not complete 0 0 replyShare Bikram commented Feb 10, 2017 reply Follow flag now corrected, Thanks. 0 0 replyShare Please log in or register to add a comment.