40 votes 40 votes Consider the quadratic equation $x^2-13x+36=0$ with coefficients in a base $b$. The solutions of this equation in the same base $b$ are $x=5$ and $x=6$. Then $b=$ _____ Set Theory & Algebra gatecse-2017-set2 polynomials numerical-answers set-theory&algebra + – khushtak asked Feb 14, 2017 • retagged Dec 29, 2017 by krish__ khushtak 14.6k views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Deepak Poonia commented Mar 29, 2020 reply Follow Share $x^2 -13x+36 = 0$ Roots = 5,6 Hence, $x=5,6$ will satisfy this given equation. Putting, $x=5,$ $(5)_b * (5)_b - (13)_b*(5)_b+(36)_b=(0)_b$ Converting everything in base 10, $25-(b+3)5+3b+6=0$ $b=8$ 29 votes 29 votes Balwinder Pal Singh commented Jan 13, 2022 reply Follow Share roots are incorrect its should be 4 an 9 so i think question is mathematically in correct?? 0 votes 0 votes Thadymademe commented Aug 12, 2022 reply Follow Share roots are 4 and 9 in decimal. not in base b 1 votes 1 votes Please log in or register to add a comment.
0 votes 0 votes Base is 8. Solve the equation by expanding the coefficients in decimal form. tvkkk answered Feb 14, 2017 tvkkk comment Share Follow See all 0 reply Please log in or register to add a comment.