0 0 votes A disk unit has 20 recording surfaces. It has a total of 14,000 cylinders. There is an average of 400 sectors per track and each sector contains 512 bytes of data. Find the storage capacity of the disk unit. If disk rotates at a speed of 7200 rpm then what is the data transfer rate in bytes per second? Do we need to multiple answer with 20 assuming that all surfaces are transferring data in parallel or not?I have a solution manual but in that it is not multipled with 20 but most of the questions in Go i have seen which multiplies it with no. of surfaces.Please clarify? CO & Architecture co-and-architecture disk + – rahul sharma 5 1.9k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Gate Madrista commented Jun 13, 2017 reply Follow flag It would be multiplied when we have 20 read/write heads.If just one read/write head no need to do that 0 0 replyShare A_i_$_h commented Jun 26, 2017 reply Follow flag i think by default we should consider multiplying with the number of surfaces questions ive come across till now hasnt mentioned anything regarding the number of read/write heads explicitly correct me if i am wrong 0 0 replyShare Please log in or register to add a comment.
0 0 votes The Capacity of the disk is = no. of surface *Total no. of Track. * no. sector * size of a single sector the Data Transfer of in 1 Sec = time for i 1 rotation =60/7200=6/720=1/120 sec in 1 sec disk rotate =120 time than data transfer rate =120*size of one track Rackson answered Oct 5, 2018 Rackson comment Share Follow 0 reply Please log in or register to add a comment.
