Question about Regular Expression

Question

Answer 1

There is no dependency among *.
you can consider any * >=0 that generate your String.
Ex.
(b*a*bab*)* +b*
the language L ={all strings contains even no of a's}
let # a's =0
strings are b, bb,bbb,bbbb,bbbbbbbb, ...  (any # of bs)

So we can consider * = 1,2,3,4,...

lets s= baabaa
(b¹ab⁰ab^₀₎2

or

(b¹ab⁰ab¹)¹(b⁰ab⁰ab⁰)¹

Comments

@Arnab, sorry to bother you, but in this R.E (b*a*bab*)* +b*

if I put *=1 in the outer * and +b*, so, will I get this string - 

(b*a*bab*) +b

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here + and * are operator not a symbol.
this two operator are used to generate a string
in final string does not contain any operator.
Draw NFA for the gammer and try to accept strings then you will get clear idea.

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Yes. I'll see that.