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12 12 votes

The probability that two friends are born in the same month is ____ ?

  1. $1/6$
  2. $1/12$
  3. $1/144$
  4. $1/24$

4 Answers

Best answer
35 35 votes

Let us say that what is the probability that they are not born in same month?

A can be born in any of 12 months and B can be born in any of the remaining 11 months $\Rightarrow$ Total possible cases = 12 x 11 = 132

Total Sample space with us : 12 x 12 = 144

$\Rightarrow$ The probability that they are not born in same month = $\frac{132}{144}$

$\Rightarrow$ The probability that they are born in the same month $1 - \frac{132}{144} = \frac{12}{144} \Rightarrow \frac{1}{12}$


Alternatively,

Let the first friend be born in any of the 12 months. For the second friend we have 12 cases and only 1 is favorable. So, probability = $\frac{12}{12} \times \frac{1}{12} \implies \frac{12}{144} \implies \frac{1}{12}$

edited by
10 10 votes
$Total\ outcomes = 12*12 =144$

$Favourable\ outcomes = \{$ (Jan,Jan) , (Feb,Feb), (March,March)....(Dec, Dec)$\} = 12$

$Probability = \frac{ Favourable\ outcomes}{Total \ Outcomes} = \frac{12}{12*12} = \frac{1}{12}$

$\therefore$  $B.$ is correct
1 1 vote
B) 1/12
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