$R1$ and $R2$ both are equivalence relation so $R1∩R2$ is also an equivalence relation because $\cap$ include only those pairs which are in both $R1$ and $ R2$.
Assertions (ii) is true
$R1∪R2$ is NOT an equivalence relation
see counter example over $(a,b)$ :
$R1=\{(a,a),(b,b),(a,b),(b,a)\}$ is equivalence relation
$R2=\{(a,a),(b,b),(c,b),(b,c)\}$ is equivalence relation
$R1∪R2=\{(a,a),(b,b),(a,b),(b,a),(c,b),(b,c)\}$ is NOT equivalence relation because transitive pair $(a,c)$ isn't include in it .
assertions (i) is not true
Ans is C