Consider data frames consisting of $20$ header and $1980$ data bits. Assume headers and retransmissions are overhead, ACK frames are negligible and NAK frames are $20$ bits. The error rate for data frames is $2$ percent and the error rate for NAK frames is negligible. Compute the fraction of the bandwidth that is wasted on overhead.
$(A) 2\%$
$(B) 98\%$
$(C) 97\%$
$(D) 3\%$
My Solution:
Case $1 :$ When Error Does Happen So:
Hence For sending $1980$ data bits total $2220 $ bits are transmitted ($20$ bit NACK)
So throughput $= \frac{2000}{2220} = 90.09\%$
So waste$= 9.9099\%$
Error Probabitlity is $2\% = 2%$ of $10.81% = 0.1981%$
Case $2:$ If Error doesnt occur then Normal Header Overhead is there:-
So Waste is $ = 100 - (\frac{1980}{2000})\times100 = 1%$
So total $= 1+0.1981 = 1.1981\%$
Io i chose $A$ option and its correct
My approach was right?