Operators precedence

Question

The output of the following program

main ( )

{

int a = 1, b = 2, c = 3;

printf (“%d”, a+ = (a+ = 3, 5, a));

}

Comments

I found a solution for this on stackoverflow.

https://stackoverflow.com/questions/30627110/how-will-be-operands-inside-a-3-5-a-are-going-to-dealt-or-caculated-in-or

It is somewhat confusing.

---

8?/???

---

for these types of questions refer http://www.sanfoundry.com/advanced-c-programming-questions-arithmetic-operators/

Answer 1

this is an effect of comma operator, i.e the last element is the one that is used as the value.

a+=(a+=3,5,a)

this expression evaluates a+=3 first which makes a = 4 , this result gets discarded then evaluates 5 which is also discarded and then evaluates a  which is the last element so the result we get is

a+=4

which gives 8 as the output