0 0 votes i have done it like this... p = 1-( (2C2 * 8C2) / 10C4) is this wrong ??? Algorithms + – hs_yadav 558 views answer comment Share Follow Print See all 4 Comments 4 4 Comments reply saxena0612 commented Dec 16, 2017 reply Follow flag $0.8192 \\(\frac{4}{5})^4 \ * 4_{c_1}\frac{1}{5}(\frac{4}{5})^3=2* (\frac{4}{5})^4$ 1 1 replyShare Surajit commented Dec 16, 2017 reply Follow flag this is direct binomial distribution,selecting 0 defective or 1 defective bulbs,then insert the respective probabilities. 0 0 replyShare Nitesh Choudhary commented Dec 21, 2017 reply Follow flag is it .9090 0 0 replyShare hs_yadav commented Dec 21, 2017 reply Follow flag @ Nitesh Choudhary Saxena comment is correct.... 0 0 replyShare Please log in or register to add a comment.
