T(n) = T(n-1) + T ( n-2 ) + T( n/2 ) + C
T(n- 1 ) > T ( n-2 ) && T ( n -1 ) > T ( n/2 )
IF WE IGNORE THE T ( n /2 )
so
T( n ) = 2 T ( n-1 ) + c
from master method
T ( n ) = a T ( n-b ) + n^k
a>1 than solution = O ( n^k a^n/b )
here a= 2 & k= 0
so complexity = 0 ( n^0 2^n/1 ) = 0 ( 2^n )
IF WE NOT IGNORE THE T( n /2 )
T ( n) = 3T ( n-1 ) +c
solution for is
a= 3 k = 0
complexity = O ( n^k 3^n/1 ) = 0 ( 3^n )
now my dout is we have to ignore the T ( n/2 ) or not …...thanks