0 votes 0 votes i have done it like this... p = 1-( (2C2 * 8C2) / 10C4) is this wrong ??? hs_yadav asked Dec 16, 2017 hs_yadav 320 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply saxena0612 commented Dec 16, 2017 reply Follow Share $0.8192 \\(\frac{4}{5})^4 \ * 4_{c_1}\frac{1}{5}(\frac{4}{5})^3=2* (\frac{4}{5})^4$ 1 votes 1 votes Surajit commented Dec 16, 2017 reply Follow Share this is direct binomial distribution,selecting 0 defective or 1 defective bulbs,then insert the respective probabilities. 0 votes 0 votes Nitesh Choudhary commented Dec 21, 2017 reply Follow Share is it .9090 0 votes 0 votes hs_yadav commented Dec 21, 2017 reply Follow Share @ Nitesh Choudhary Saxena comment is correct.... 0 votes 0 votes Please log in or register to add a comment.
