search
Log In
1 vote
80 views

I got answer 450 but the answer given is 410
400(to access 4 words in L2) + 40(4 access to store word read from L2 in L1) + 10(final one access by CPU) = 450

in CO and Architecture
recategorized by
80 views

Please log in or register to answer this question.

Related questions

0 votes
1 answer
3
154 views
The cache can hold 64 KB .data is transferred between main memory and cache in blocks of 4 bytes each.the main memory consist of 16 M Bytes . if the cache memory is 16-way set associative,Then the hexa decimal main memory address AAAAAA is mapped into which cache set?
asked Dec 27, 2018 in CO and Architecture Amar Khade 154 views
...