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How to solve?
________________
Number of nonnegative integer solutions such that
x+y+z=17
where x>1,y>2,z>3 is 
systemofequations
asked
Jan 13, 2018
in
Linear Algebra
by
ankit_thawal
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1.4k
points)

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answer
comment
0
Is it 45.
0
how to solve?
plzz elaborate.
+2
x+y+z=17
where x>1,y>2,z>3
x+2+y+3+z+4= 17
x+y+z= 17 9
x+y+z= 8
^{8+}
^{31}
C
_{8 }
=
^{10}
C
_{8}
= 45
0
@Anu007 there is greater than sign not greater than equal to, so x must be at least 2 , y at least 3 and z at least 4 right?
0
yeah...:)
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votes
since x>1,y>2 and z>3
so new equation will be
x+1+y+3+z+4=17
=>x+y+z=8
now no. of solution of these equations are (n+r1)C(r1)
here n=8 r=3(no. of unknowns)
so 10C2=45 Ans
answered
Jun 28, 2018
by
Navneet Kalra
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