Given a matrix of size 32K*8K
also given that the page fault of both are equal, which is only possible if the whole matrix can be stored in memory.
Further its mentioned that the number of page fault is 8K which means the page size is 32K
Now we need to find out the number of page fault caused by program2 with page size 32K
Number of page faults in program2 for a single page = 4
for each iteration of for(i = 0; i < 32768; i++) loop there will be 32K/4 page faults = 8K page faults
This is repeated for(j = 0; j < 8192; j++) number of times.
Hence total number of page faults = 8K*8K = 64M
Option D is the correct answer