Operating System closed

Question

Is ans 12 or 17?

Comments

I'm getting 17

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I am getting 17

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If 12 was the BT, then after 6 units, remaining BT for P0 would be 6

Then P2 is scheduled, thus it should be less than 6, say 5. It will execute for 4 units, then its remaining BT will be 1.

For P1 to be scheduled after this, it's BT should be less than 1, which won't be possible

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it is SRTF

then minimum 6 is already for P0

now, if we take burst time 6 more (i.e. greater than P1 and P2), then will not be it minimum??

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it only asked burst time for P0

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But we also have to consider that after P2 executes P1 has to execute

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@srestha 

In SRTF, the next process will schedule only when there is a process whose remaining burst is less than the process running in CPU right?

Here scenario is suppose P0 comes at x, it runs 6 unit till x+6, then P2 comes it runs 4 till x+10 then P1 comes and runs for 5 units, here P1 completely finished its burst till x+15 but P0 and P2 still left with their burst.

P0

P2

P1

Now, see why P1(BT: 5) is scheduled after P2 obviously, it have remaining burst lesser than P2 since min is asked take it 6(P2 min BT 10) , and now why P2 is scheduled after P0 because P2 have remaining burst less than remaining of P0(take it as 11)

P0 min BT : 6(executed already) + 11 = 17

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@Ashwani

what u r telling, is that not turn around time?

Question ask for  burst time of P0

So, why need to execute P1  and P2??

I think it is not actually needed

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https://gateoverflow.in/194995/madeeasy-test-series

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it is incomplete question ma'am.

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yes

I too think so

no satisfactory answer yet

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@srestha

mam, what's wrong with the explanation of Minipanda which is provided in the link ?

you may check this also, for solving this question