retagged by
1,477 views
2 2 votes
Minimum and maximum (-ve) mantisa range in IEEE 754 32 bit floating point number representation with 1bit for sign, 8 bit for exponent and 23 bit for mantisa.

1 Answer

Best answer
0 0 votes
i think the range will be from all zeros to all once. so mantissa can be from 1.0000000....00 to 1.11111111...111 = 1 to $2-2^{-23}$
Position:
Show:

Related questions

2 2 votes
2 answers 2 answers
7.4k
7.4k views
hemantsoni asked May 5, 2016
7,413 views
Which of the given number has its IEEE-754 32-bit floating-point representation as $(0 \ 10000000\ 110 0000 0000 0000 0000 0000)$a) 2.5b) 3.0c) 3.5d) 4.5
5 5 votes
0 0 answers
2.4k
2.4k views
Manu Thakur asked Jan 14, 2018
2,407 views
Can someone please validate if the given range is correct, and we can keep all 0's in Mantissa unlike biased exponent.
0 0 votes
1 1 answer
1.0k
1.0k views
8 8 votes
2 2 answers
6.1k
6.1k views
Shubhanshu asked Sep 3, 2017
6,143 views
16 bit Floating Point Representation$(-1)^{sign}*(1.M)*2^{Exp - 63}$Sign = 1 bitExponent = 7 bitMantissa = 8 bit1) Max positive number2) Min positive number.3) Max negati...