11,778 views

1 Answer

Best answer
5 votes
5 votes
Throughput of pure aloha ,S=G × $e^{-2G}$. Where G is the average no. Of frames generated by system during one frame transmission time.

Transmission time =$\frac{frame size} {bandwidth}$=$\frac{200 bits}{200kbps}$=1 ms.

If system create 1000 frames per second  means  1 frame  per millisecond ,so G=1

S=$G×e^{-2G}$=0.135 that means throughput is 1000×.135=135 frames.only 135 frame out of 1000 will survive.
selected by

Related questions

4.7k
views
0 answers
0 votes
soso asked Nov 2, 2018
4,701 views
I have done the calculations as shown below but I do not know if my approach is correct. I would appreciate if I get some feedbackPart 1Consider ... connected?Calculate the throughput of the network for the given number of terminals.
7.9k
views
1 answers
1 votes
Abhishek Malik asked May 21, 2018
7,945 views
An aloha network user $19.2 \text{ kbps}$ channel for sending message packets of $100 \text{ bits}$ longsize. calculate the maximum throughput for pure aloha network.
4.7k
views
1 answers
5 votes
MiNiPanda asked Jan 8, 2018
4,694 views
Groups of user stations(N) share a 56Kbps pure aloha channel. Each station outputs a 1000 bits frame on an average of once every 100sec(stations are buffered). What is the max value of N?Answer is 1030. Please give detailed solution.
8.1k
views
1 answers
1 votes
LavTheRawkstar asked Apr 5, 2017
8,145 views
A Pure Aloha transmits 200 bits frame on a shared channel of 200 kbps.What is time required to make Frame Collision free?