Given information:
- P(X) = 0.60 (60% from supplier X)
- P(Y) = 0.40 (40% from supplier Y)
- P(Reliable|X) = 0.96 (96% of X's are reliable)
- P(Reliable|Y) = 0.72 (72% of Y's are reliable)
Find: P(Y|Reliable)
Step 1: Find the total probability of getting a reliable shock absorber
Using the Law of Total Probability:
P(Reliable):
= P(Reliable∣X)⋅P(X) + P(Reliable∣Y)⋅P(Y)
= 0.96*0.60 + 0.72*0.40
= 0.576+0.288
= 0.864
Step 2: Apply Bayes' Theorem
P(Y∣Reliable):
= P(Y∩Reliable) / P(Reliable)
= P(Reliable∣Y)⋅P(Y) / P(Reliable)
= 0.72*0.40 / 0.864
= 0.288 / 0.864
= 1/3
= 0.3333 or 0.334