A Bayes theorem question which can be solved easily using the tree diagram.
Conditional probabilities given in question are represented above in the tree diagram.
The green edges indicate the probability of Guwahati having high, medium or low temperatures.
The blue edges after each yellow edge show the probability of having high, medium or low temperature in Delhi provided, a high, medium or low temperature in Guwahati.
It is asked
probability (correct to two decimal places) that Guwahati has high temperature given that Delhi has high temperature
which is given by
P(HG | HD) = $\frac{P(H_{G} \cap H_{D})}{P(H_{D})}$
P(HG$\cap$HD) = probability that Delhi has high temperature and Guwahati has high temperature = 0.2*0.4 = 0.08
P(HD) = Probability that Delhi has high temperature is given by a taken sum of all high-temperature cases in Delhi, regardless of what temperature in Guwahati is(High, Medium or low). i.e. Take the sum of all such conditional probabilities. Marked by yellow bubbles in the diagram.
P(HD) = (0.2*0.4) + (0.5*0.10) + (0.3*0.01) = 0.133
So, P(HG | HD) = $\frac{0.08}{0.133} = 0.601$